È˽̰æ¾ÅÄ꼶ÉϲáÊýѧ×÷Òµ±¾µÚ¶þÊ®¶þÕÂ22.1.3¶þ´Îº¯Êýy=a£¨x-h£©2+kµÄͼÏñºÍÐÔÖÊ£¨2£©´ð°¸½Î÷Ê¡
1µÚ¶þÊ®¶þÕÂ22.1.3¶þ´Îº¯Êýy=a£¨x-h£©2+kµÄͼÏñºÍÐÔÖÊ£¨2£©µÚÒ»Ìâ´ð°¸
£¨h£¬k£©£»Ö±Ïßx=h£»h£»k£» 2µÚ¶þÊ®¶þÕÂ22.1.3¶þ´Îº¯Êýy=a£¨x-h£©2+kµÄͼÏñºÍÐÔÖÊ£¨2£©µÚ¶þÌâ´ð°¸ ÓÒ£»3£»ÉÏ£»4 3µÚ¶þÊ®¶þÕÂ22.1.3¶þ´Îº¯Êýy=a£¨x-h£©2+kµÄͼÏñºÍÐÔÖÊ£¨2£©µÚÈýÌâ´ð°¸ y=-2£¨x+2£©2-3 4µÚ¶þÊ®¶þÕÂ22.1.3¶þ´Îº¯Êýy=a£¨x-h£©2+kµÄͼÏñºÍÐÔÖÊ£¨2£©µÚËÄÌâ´ð°¸ £¨3£¬4£© 5µÚ¶þÊ®¶þÕÂ22.1.3¶þ´Îº¯Êýy=a£¨x-h£©2+kµÄͼÏñºÍÐÔÖÊ£¨2£©µÚÎåÌâ´ð°¸ Ö±Ïßx=-2 6µÚ¶þÊ®¶þÕÂ22.1.3¶þ´Îº¯Êýy=a£¨x-h£©2+kµÄͼÏñºÍÐÔÖÊ£¨2£©µÚÁùÌâ´ð°¸ ½â£º£¨1£©ÏÈÏòÓÒƽÒÆ3¸öµ¥Î»³¤¶È£¬ÔÙÏòÉÏƽÒÆ2¸öµ¥Î»³¤¶È¡£
£¨2£©¿ª¿ÚÏòÏ£¬¶Ô³ÆÖáÊÇÖ±Ïßx=3£¬¶¥µã×ø±êÊÇ£¨3£¬2£©£®
£¨3£©ÏÈÏò×óƽÒÆ4¸öµ¥Î»³¤¶È£¬ÔÙÏòÏÂƽÒÆ3¸öµ¥Î»³¤¶È¡£ 7µÚ¶þÊ®¶þÕÂ22.1.3¶þ´Îº¯Êýy=a£¨x-h£©2+kµÄͼÏñºÍÐÔÖÊ£¨2£©µÚÆßÌâ´ð°¸ ½â£º£¨1£©¡ßÅ×ÎïÏ߶¥µã×ø±êΪ£¨-3£¬-3£¬ ¡àÉè´ËÅ×ÎïÏߵĽâÎöʽΪy=a£¨x+3£©2 -3 ¡ßÅ×ÎïÏß¾¹ýԵ㣬